From a bit of Googling, it looks like the average is 2-5 mL, so let’s say this is a completely average man and split it down the middle at 3.5 mL of ♥♥♥ per ejaculation, with adequate rest between each session so we don’t get any dry runs.

Second, how much does semen weigh? The common consensus seems to be a density of 1.0 g/mL, so let’s use that. To get weight from density, we have to calculate mass using the figures we already know. Density equals mass/volume (our average amount of semen), so 1.0 = m/3.5, which converts to m = 1.03.5, which ends up as m = 3.5g, which we’ll convert into kilograms, at 0.0035kg. Easy enough. Now, we calculate the weight, which equals massgravitational acceleration (which is a constant of 9.8 meters/second2 on the Earth’s surface). So w = 0.0035 * 9.8, therefore, our weight is 0.0343N (newtons, the SI unit for weight). Since we want a pound of ♥♥♥, let’s translate that to ounces, which is around 0.12oz, rounded.

So, we have 0.12oz of ♥♥♥ per average ejaculation, and our final calculation will be getting that up to a pound. One pound is 16 ounces, so 16/0.12= 133.333333. So, an average male would have to ejaculate about 134 times to produce one pound of ♥♥♥.

So no, you can't produce a pound ♥♥♥ In one ejaculation.